X^4/3-5x2/3+6=0

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Solution for X^4/3-5x2/3+6=0 equation: 


x in (-oo:+oo)

(X^4)/3-((5*x^2)/3)+6 = 0

(X^4)/3+(-5/3)*x^2+6 = 0

-5/3*x^2 = -(1/3*X^4+6) // : -5/3

x^2 = 3/5*(1/3*X^4+6)

x^2 = 3/5*(1/3*X^4+6) // ^ 1/2

abs(x) = (3/5)^(1/2)*(1/3*X^4+6)^(1/2)

x = (3/5)^(1/2)*(1/3*X^4+6)^(1/2) or x = -((3/5)^(1/2)*(1/3*X^4+6)^(1/2))

x in { (3/5)^(1/2)*(1/3*X^4+6)^(1/2), -((3/5)^(1/2)*(1/3*X^4+6)^(1/2)) }

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